(128)^x=(1/2)^2x-3

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Solution for (128)^x=(1/2)^2x-3 equation:



(128)^x=(1/2)^2x-3
We move all terms to the left:
(128)^x-((1/2)^2x-3)=0
Domain of the equation: 2)^2x-3)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
128^x-((+1/2)^2x-3)=0
We multiply all the terms by the denominator
128^x*2)^2x-3)-((+1=0
Wy multiply elements
256x^2+1=0
a = 256; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·256·1
Δ = -1024
Delta is less than zero, so there is no solution for the equation

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